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0.4x^2+7.2x=3.6
We move all terms to the left:
0.4x^2+7.2x-(3.6)=0
We add all the numbers together, and all the variables
0.4x^2+7.2x-3.6=0
a = 0.4; b = 7.2; c = -3.6;
Δ = b2-4ac
Δ = 7.22-4·0.4·(-3.6)
Δ = 57.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.2)-\sqrt{57.6}}{2*0.4}=\frac{-7.2-\sqrt{57.6}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.2)+\sqrt{57.6}}{2*0.4}=\frac{-7.2+\sqrt{57.6}}{0.8} $
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